Velvet Tears Posted June 20, 2008 Posted June 20, 2008 The manager had the same anniversary(day and year), and he didn't get married on a Sunday.
phee Posted June 20, 2008 Author Posted June 20, 2008 The manager had the same anniversary(day and year), and he didn't get married on a Sunday. Closer... but not quite.... the manager we will say is Not Married in this one
hunhee Posted June 20, 2008 Posted June 20, 2008 Days are predictable, and given a day and a year, you can follow what day they will land on (there's a 28 year repetitive pattern). If it's exactly 28 years to the day, and they were there (at the restaurant) on a Thursday, the day they got married would be on Thursday.. not Sunday..
Fin Posted June 20, 2008 Posted June 20, 2008 There are 3 possibilities: 1--The manager is the woman's husband & knows this date is wrong, 2--The woman is "married" to another woman. Gay weddings were not legal 28 years ago, or (& I suspect this is the "official" answer to your riddle) 3--Every 28 years, calendar dates & days of the week line up exactly. Therefore, since this day is a Thursday, there is no way that the couple could have been married 28 years ago on a Sunday if this is, indeed, their anniversary.
hunhee Posted June 20, 2008 Posted June 20, 2008 There are 3 possibilities: 1--The manager is the woman's husband & knows this date is wrong, 2--The woman is "married" to another woman. Gay weddings were not legal 28 years ago, or (& I suspect this is the "official" answer to your riddle) 3--Every 28 years, calendar dates & days of the week line up exactly. Therefore, since this day is a Thursday, there is no way that the couple could have been married 28 years ago on a Sunday if this is, indeed, their anniversary. I beat you to it.. heh
Fin Posted June 20, 2008 Posted June 20, 2008 I beat you to it.. heh Oh GREAT. And here I am pontificating about possible other solutions. You pirate.
phee Posted June 20, 2008 Author Posted June 20, 2008 Days are predictable, and given a day and a year, you can follow what day they will land on (there's a 28 year repetitive pattern). If it's exactly 28 years to the day, and they were there (at the restaurant) on a Thursday, the day they got married would be on Thursday.. not Sunday.. CORRECT!!!!!! In Detroit, if you drop a steel ball weighing five pounds from a height of 45 inches, will it fall more rapidly through water at 20 degrees Fahrenheit or water at 40 degrees Fahrenheit. Or will it make no difference?
hunhee Posted June 20, 2008 Posted June 20, 2008 Oh GREAT. And here I am pontificating about possible other solutions. You pirate. Pirate?!?!?! Just because you were slower at the button than me.. *gives you raspberries* hehe
Fin Posted June 20, 2008 Posted June 20, 2008 CORRECT!!!!!!In Detroit, if you drop a steel ball weighing five pounds from a height of 45 inches, will it fall more rapidly through water at 20 degrees Fahrenheit or water at 40 degrees Fahrenheit. Or will it make no difference? Water @ 20 F is frozen. The ball will not fall through a block of ice.
hunhee Posted June 20, 2008 Posted June 20, 2008 CORRECT!!!!!!In Detroit, if you drop a steel ball weighing five pounds from a height of 45 inches, will it fall more rapidly through water at 20 degrees Fahrenheit or water at 40 degrees Fahrenheit. Or will it make no difference? Water is frozen at 32 degrees Fahrenheit, so umm.. yeah.. it does matter. It won't fall THROUGH the water at 20 degrees but it will fall through water at 40 degrees.
hunhee Posted June 20, 2008 Posted June 20, 2008 Water @ 20 F is frozen. The ball will not fall through a block of ice. Damn you and your little dog too!!!!
Fin Posted June 20, 2008 Posted June 20, 2008 Pirate?!?!?! Just because you were slower at the button than me.. *gives you raspberries* hehe What--you don't like a man with a slow hand?
hunhee Posted June 20, 2008 Posted June 20, 2008 What--you don't like a man with a slow hand? umm.. uhh.. you're purposely trying to distract me so that you can get to the answers faster.. *shakes angry fist*
phee Posted June 20, 2008 Author Posted June 20, 2008 Water @ 20 F is frozen. The ball will not fall through a block of ice. YUP One man shows another, the portrait of a gentleman and tells him: "I have neither brothers nor sisters, but this man's father is the son of my father." Who is the man in the painting?
hunhee Posted June 20, 2008 Posted June 20, 2008 YUPOne man shows another, the portrait of a gentleman and tells him: "I have neither brothers nor sisters, but this man's father is the son of my father." Who is the man in the painting? It's a self portrait? It reminds me of the Spaceballs quote.. Dark Helmet: "I am your father's brother's nephew's cousin's former roommate."
phee Posted June 20, 2008 Author Posted June 20, 2008 It's a self portrait? It reminds me of the Spaceballs quote.. Dark Helmet: "I am your father's brother's nephew's cousin's former roommate." Nope
phee Posted June 20, 2008 Author Posted June 20, 2008 D'oH.. his son. INDEED You are given 18 silver coins but you find out that one of the coins(you kon't know which ) is fake and weighs less than any of the others. How can you be able to detect the false coin using a normal balance scale only three times?
hunhee Posted June 20, 2008 Posted June 20, 2008 Oops.. this is what I meant.. heh Weigh ONE Divide the 18 coins into three piles.. weigh two out of the three.. So you have.. 3 piles of 6 If they're equal you know the bogus one is in the third pile.. (If they're not equal, either way, you know which pile is the bogus pile) Weigh TWO So now you have 6 coins that you have to work with.. divide that into two piles.. 2 piles of 3 Weigh those, which ever one is less, you take that one (now you're down to three coins).. Weigh THREE weigh 1 against 1 If those two are equal, the one you left out is the bogus one.. or if one is less than the other, you know which one is the bogus one.
Fin Posted June 20, 2008 Posted June 20, 2008 I'm gonna fire one back @ Phee: Duncan is half his father Dougal's age. In 10 years, Duncan will be three-fifths Dougal's age. Ten years ago, Duncan was one-third Dougal's age. How old are Dougal and Duncan now?
phee Posted June 20, 2008 Author Posted June 20, 2008 Oops.. this is what I meant.. heh Divide the 18 coins into three piles.. weigh two out of the three.. So you have.. 3 piles of 6 If they're equal you know the bogus one is in the third pile.. So now you have 6 coins that you have to work with.. divide that into two piles.. 2 piles of 3 Weigh those, which ever one is less, you take that one (now you're down to three coins).. weigh 1 against 1 If those two are equal, the one you left out is the bogus one.. or if one is less than the other, you know which one is the bogus one. Correct... No legs have I to dance, No lungs have I to breathe, No life have I to live or die And yet I do all three. What am I?
Fin Posted June 20, 2008 Posted June 20, 2008 Correct... No legs have I to dance, No lungs have I to breathe, No life have I to live or die And yet I do all three. What am I? ANSWER: An open flame Now try to answer MINE (See above)
phee Posted June 20, 2008 Author Posted June 20, 2008 I'm gonna fire one back @ Phee: Will get back to you on that
Fin Posted June 20, 2008 Posted June 20, 2008 Will get back to you on that This one's fun, too--& not such a mental pretzler: Two folks, starting at the same point, walk in opposite directions for 4 meters, turn left and walk another 3 meters. What is the distance between them?
Rev.Reverence Posted June 20, 2008 Posted June 20, 2008 This one's fun, too--& not such a mental pretzler: Two folks, starting at the same point, walk in opposite directions for 4 meters, turn left and walk another 3 meters. What is the distance between them? 10meters! That is Pythagoras! Not a riddle! Basic math!
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